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Q. Consider the reaction sequence from $P$ to $Q$ shown below. The overall yield of the major product $Q$ from $P$ is $75 \%$. What is the amount in grams of $Q$ obtained from $9.3 \,mL$ of $P ?$ (Use density of $P =1.00 \,g \,mL ^{-1}$; Molar mass of $C =12.0, H =1.0, O =16.0$ and $N =14.0 \,g \,mol ^{-1}$ )Chemistry Question Image

JEE AdvancedJEE Advanced 2020

Solution:

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Moles of $P=\frac{9.3}{93}=0.1=$ moles of $Q$.
So, mass of $(Q)=0.1 \times 248 \times 0.75=18.60$ gram