Question

Consider the reaction,
$4N{O}_2\left(g\right)+O_2\left(g\right)\to 2N_2{O}_5\left(g\right),\Delta H=-111kJ$ If $N_2{O}_5\left(s\right)$
is formed instead of $N_2{O}_5\left(g\right)$ in the above reaction, the $\Delta H$ value will be (Given, $\Delta H$ of sublimation for $N_2{O}_5$ is $54kJmo{l}^{-1})$

• A. $-165kJ$
• B. $+54kJ$
• C. $+219kJ$
• D. $-219kJ$

Answer 1

Answer: (D)

Correct answer is (d) $-219kJ$