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Q. Consider the reaction,
$4NO_{2}\left(g\right)+O_{2}\left(g\right)\to2N_{2}O_{5}\left(g\right),\Delta H=-111\, kJ$ If $N_{2}O_{5}\left(s\right)$
is formed instead of $N_2O_5\left(g\right)$ in the above reaction, the $\Delta H$ value will be (Given, $\Delta H$ of sublimation for $N_2O_5$ is $54\, kJ\, mol^{-1})$

Thermodynamics

Solution:

Correct answer is (d) $-219\, kJ$

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