Q.
Consider the reaction,
$4NO_{2}\left(g\right)+O_{2}\left(g\right)\to2N_{2}O_{5}\left(g\right),\Delta H=-111\, kJ$ If $N_{2}O_{5}\left(s\right)$
is formed instead of $N_2O_5\left(g\right)$ in the above reaction, the
$\Delta H$ value will be
(Given, $\Delta H$ of sublimation for $N_2O_5$ is $54\, kJ\, mol^{-1})$
Thermodynamics
Solution:
Correct answer is (d) $-219\, kJ$
