Consider the nuclear reaction X 200 arrow A 110+ B 90 If the binding energy per nucleon for X , A and B is 7.4 MeV , 8.2 MeV and 8.2 MeV respectively, then the amount of the energy released is

Question

Consider the nuclear reaction X 200 arrow A 110+ B 90 If the binding energy per nucleon for X , A and B is 7.4 MeV , 8.2 MeV and 8.2 MeV respectively, then the amount of the energy released is (A) 200 MeV (B) 160 MeV (C) 110 MeV (D) 90 MeV

Tardigrade Admin · Accepted Answer

Initial BE =7.4 × 200 MeV Final BE =8.2 × 110+8.2 × 90 MeV ∴ Energy release = Final - Initial =(8.2-7.4) × 200=0.8 × 200 =160 MeV

Q. Consider the nuclear reaction $X^{200} \to A^{110} + B^{90}$ If the binding energy per nucleon for $X, A$ and $B$ is $7.4 M e V, 8.2 M e V$ and $8.2 M e V$ respectively, then the amount of the energy released is

200 MeV

160 MeV

110 MeV

90 MeV

Initial $BE = 7.4 \times 200 M e V$
Final $BE = 8.2 \times 110 + 8.2 \times 90 M e V$
$∴$ Energy release $=$ Final $-$ Initial
$= (8.2 - 7.4) \times 200 = 0.8 \times 200$
$= 160 M e V$

Q. Consider the nuclear reaction X200→A110+B90 If the binding energy per nucleon for X,A and B is 7.4MeV,8.2MeV and 8.2MeV respectively, then the amount of the energy released is