Q.
Consider the non-empty set consisting of children in a family and a relation R defined as aRb if a is brother of b. Then R is
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Relations and Functions - Part 2
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Solution:
Given aRb⇒a is brother of b.
But bRa[∵b may or may not be brother of a] ∴R is not symmetric.
Let aRb and bRc ⇒a is brother of b and b is brother of c. ∴a is brother of c⇒(a, c)∈R. ∴R is transitive.