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Q. Consider the non-empty set consisting of children in a family and a relation $R$ defined as $aRb$ if $a$ is brother of $b$. Then $R$ is

Relations and Functions - Part 2

Solution:

Given $aRb \Rightarrow a$ is brother of $b$.
But $b\, \not \,R \,a \,[ \because b$ may or may not be brother of $a]$
$\therefore R$ is not symmetric.
Let $aRb$ and $bRc$
$ \Rightarrow a$ is brother of $b$ and $b$ is brother of $c$.
$\therefore a$ is brother of $c \Rightarrow (a$, $c)\in R$.
$\therefore R$ is transitive.