Consider the nitration of benzene using mixed conc. H2SO4 and HNO3. If a large amount of KHSO4 is added to the mixture, the rate of nitration will be :

Question

Consider the nitration of benzene using mixed conc. H2SO4 and HNO3. If a large amount of KHSO4 is added to the mixture, the rate of nitration will be : (A) slower (B) uncharged (C) doubled (D) faster

Tardigrade Admin · Accepted Answer

H2SO4 + overset⊕ H arrow NO2 + H overset ominusS O4 + H2O KHSO4 arrow K⊕ + H overset ominusSO4 Due to common ion effect backward reaction will take place so the formation NO+2 decrease so nitration process will become slower.

Q. Consider the nitration of benzene using mixed conc. $H_{2} S O_{4}$ and $H N O_{3}$ . If a large amount of $KH S O_{4}$ is added to the mixture, the rate of nitration will be :

slower

uncharged

doubled

faster

$H_{2} S O_{4} + H \oplus \to N O_{2} + H S ⊖ O_{4} + H_{2} O$
$KH S O_{4} \to K^{\oplus} + H S ⊖ O_{4}$
Due to common ion effect backward reaction will take place so the formation $N O_{2}^{+}$ decrease so nitration process will become slower.

Q. Consider the nitration of benzene using mixed conc. H2​SO4​ and HNO3​. If a large amount of KHSO4​ is added to the mixture, the rate of nitration will be :