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Q.
Consider the nitration of benzene using mixed conc. $ H_2SO_4$ and $HNO_3$. If a large amount of $KHSO_4$ is added to the mixture, the rate of nitration will be :
$H_2SO_4 + \overset{\oplus }{H} \rightarrow NO_2 + H\overset{\ominus}{S} O_4 + H_2O $
$KHSO_4 \rightarrow K^{\oplus} + H \overset{\ominus}{S}O_4$
Due to common ion effect backward reaction will take place so the formation $NO^{+}_{2}$ decrease so nitration process will become slower.