Question

Consider the junction diode as ideal. The value of current flowing through $AB$ is :

• A. $10^{-2}A$
• B. $10^{-1}A$
• C. $10^{-3}A$
• D. $0A$

Answer 1

Answer: (A)

Since diode is in forward bias $i=\frac{\Delta V}{R}=\frac{4-(-6)}{1\times 10^3}=\frac{10}{10^3}=10^{-2}A$