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Q. Consider the junction diode as ideal. The value of current flowing through $AB$ is :Physics Question Image

NEETNEET 2016Semiconductor Electronics: Materials Devices and Simple Circuits

Solution:

Since diode is in forward bias $ i = \frac{\Delta V}{R} = \frac{4 - (-6)}{1 \times 10^{3}} = \frac{10}{10^3} = 10^{-2} A $