Consider the ground state of Cr atom ( Z =24) . The summation of numbers of electrons with the azimuthal quantum numbers, l=1 and 2 will be

Question

Consider the ground state of Cr atom ( Z =24) . The summation of numbers of electrons with the azimuthal quantum numbers, l=1 and 2 will be (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

l=1 for p and l=2 for d. Now 24 Cr has configuration 1 s2 2 s2 2 p6 3 s2 3 p6 3 d5 4 s1 Hence, there are 12 p-electrons and 5 d-electrons.

Q. Consider the ground state of $C r$ atom $(Z = 24) .$ The summation of numbers of electrons with the azimuthal quantum numbers, $l = 1$ and $2$ will be

$l = 1$ for $p$ and $l = 2$ for $d$ .
Now $_{24}$ Cr has configuration $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{5} 4 s^{1}$
Hence, there are $12 p$ -electrons and $5 d$ -electrons.

Q. Consider the ground state of Cr atom (Z=24). The summation of numbers of electrons with the azimuthal quantum numbers, l=1 and 2 will be

l=1 for p and l=2 for d. Now 24​ Cr has configuration 1s22s22p63s23p63d54s1 Hence, there are 12p-electrons and 5d-electrons.

Q. Consider the ground state of $C r$ atom $(Z = 24) .$ The summation of numbers of electrons with the azimuthal quantum numbers, $l = 1$ and $2$ will be

$l = 1$ for $p$ and $l = 2$ for $d$ .
Now $_{24}$ Cr has configuration $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{5} 4 s^{1}$
Hence, there are $12 p$ -electrons and $5 d$ -electrons.