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Q. Consider the ground state of $Cr$ atom $( Z =24) .$ The summation of numbers of electrons with the azimuthal quantum numbers, $l=1$ and $2$ will be

Structure of Atom

Solution:

$l=1$ for $p$ and $l=2$ for $d$.
Now ${ }_{24}$ Cr has configuration $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{5} 4 s^{1}$
Hence, there are $12 p$-electrons and $5 d$-electrons.