Consider the following reversible chemical reactions: A 2( g )+ B 2( g ) xrightleftharpoonsK1 2 AB ( g ) ldots .(1) 6 AB ( g ) xrightleftharpoonsK2 3 A 2( g )+3 B 2( g ) ldots(2) The relation between K1 and K2 is :

Question

Consider the following reversible chemical reactions: A 2( g )+ B 2( g ) xrightleftharpoonsK1 2 AB ( g ) ldots .(1) 6 AB ( g ) xrightleftharpoonsK2 3 A 2( g )+3 B 2( g ) ldots(2) The relation between K1 and K2 is : (A) K2 = K13 (B) K2 = K1-3 (C) K1 K2 = 3  (D) K1 K2 = (1/3)

Tardigrade Admin · Accepted Answer

A 2( g )+ B 2( g ) xrightleftharpoonsk1 2 AB ldots . .(1) ⇒ e q ⋅(1) × 3 6 AB ( g ) leftharpoons 3 A 2( g )+3 B 2( g ) ⇒((1/k1))3=k2 ⇒ k2=(k1)-3

Q. Consider the following reversible chemical reactions:
$A_{2} (g) + B_{2} (g) K_{1} 2 A B (g) \dots . (1)$
$6 A B (g) K_{2} 3 A_{2} (g) + 3 B_{2} (g) \dots (2)$
The relation between $K_{1}$ and $K_{2}$ is :

$K_{2} = K_{1}^{3}$

$K_{2} = K_{1}^{- 3}$

$K_{1} K_{2} = 3$

$K_{1} K_{2} = \frac{1}{3}$

$A_{2} (g) + B_{2} (g) k_{1} 2 A B \dots .. (1)$
$\Rightarrow e q \cdot (1) \times 3$
$6 A B (g) ⇌ 3 A_{2} (g) + 3 B_{2} (g)$
$\Rightarrow (\frac{1}{k _{1}})^{3} = k_{2} \Rightarrow k_{2} = (k_{1})^{- 3}$

Q. Consider the following reversible chemical reactions: A2​(g)+B2​(g)K1​​2AB(g)….(1) 6AB(g)K2​​3A2​(g)+3B2​(g)…(2) The relation between K1​ and K2​ is :

K2​=K13​

K2​=K1−3​

K1​K2​=3

K1​K2​=31​