Q. Consider the following relations for emf of an electrochemical cell
EMF of cell = (oxidation potential of anode) - (Reduction potential of cathode)
EMF of cell = (oxidation potential of anode) + (Reduction potential of cathode)
EMF of cell = (reduction potential of anode) + (oxidation potential of cathode)
EMF of cell = (oxidation potential of anode) - (oxidation potential of cathode)
Which of these expressions are correct?

 94  178 NTA AbhyasNTA Abhyas 2022 Report Error

Solution:

EMF of a cell = reduction potential of cathode - reduction potential of anode
= reduction potential of cathode + oxidation potential of anode
= oxidation potential of anode - oxidation potential of cathode.