1. Tardigrade
  2. Question
  3. Chemistry
  4. Consider the following relations for emf of an electrochemical cell (.i.) EMF of cell = (oxidation potential of anode) - (Reduction potential of cathode) (.ii.) EMF of cell = (oxidation potential of anode) + (Reduction potential of cathode) (.iii.) EMF of cell = (reduction potential of anode) + (oxidation potential of cathode) (.iv.) EMF of cell = (oxidation potential of anode) - (oxidation potential of cathode) Which of these expressions are correct?

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Q. Consider the following relations for emf of an electrochemical cell
$\left(\right.i\left.\right)$ EMF of cell = (oxidation potential of anode) - (Reduction potential of cathode)
$\left(\right.ii\left.\right)$ EMF of cell = (oxidation potential of anode) + (Reduction potential of cathode)
$\left(\right.iii\left.\right)$ EMF of cell = (reduction potential of anode) + (oxidation potential of cathode)
$\left(\right.iv\left.\right)$ EMF of cell = (oxidation potential of anode) - (oxidation potential of cathode)
Which of these expressions are correct?

NTA AbhyasNTA Abhyas 2022

Solution:

EMF of a cell = reduction potential of cathode - reduction potential of anode
= reduction potential of cathode + oxidation potential of anode
= oxidation potential of anode - oxidation potential of cathode.