Consider the following reactions (1) ( CH 3)3 CCH ( OH ) CH 3 xrightarrow text conc. H 2 SO 4 (2) ( CH 3)2 CHCH ( Br ) CH 3 xrightarrow text conc. KOH (3) ( CH 3)2 CHCH ( Br ) CH 3 xrightarrow( CH 3)3 CO ominus K ⊕ (4) Which of these reactions(s) will produce Saytzeff product?

Question

Consider the following reactions (1) ( CH 3)3 CCH ( OH ) CH 3 xrightarrow text conc. H 2 SO 4 (2) ( CH 3)2 CHCH ( Br ) CH 3 xrightarrow text conc. KOH (3) ( CH 3)2 CHCH ( Br ) CH 3 xrightarrow( CH 3)3 CO ominus K ⊕ (4) <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/c-sonf9kj4m3nj.png" /> Which of these reactions(s) will produce Saytzeff product? (A) (1), (2) and (4) (B) (3) only (C) (4) only (D) (2) and (4)

Tardigrade Admin · Accepted Answer

Bulky base like ( CH 3)3 O ominus K ⊕ always prefers Hoffmann product (less stable alkene) in case of 1, 2 and 4 elimination product are according to Saytzeff Rule (more stable alkene)

Q. Consider the following reactions
(1) $(C H_{3})_{3} CC H (O H) C H_{3} conc. H_{2} S O_{4}$
(2) $(C H_{3})_{2} C H C H (B r) C H_{3} conc. K O H$
(3) $(C H_{3})_{2} C H C H (B r) C H_{3} (C H_{3})_{3} C O^{⊖} K^{\oplus}$
(4)

Which of these reactions(s) will produce Saytzeff product?

(1), (2) and (4)

(3) only

(4) only

(2) and (4)

Bulky base like $(C H_{3})_{3} O^{⊖} K^{\oplus}$ always prefers Hoffmann product (less stable alkene) in case of 1, 2 and 4 elimination product are according to Saytzeff Rule (more stable alkene)

Q. Consider the following reactions (1) (CH3​)3​CCH(OH)CH3​ conc. H2​SO4​​ (2) (CH3​)2​CHCH(Br)CH3​ conc. KOH​ (3) (CH3​)2​CHCH(Br)CH3​(CH3​)3​CO⊖K⊕​ (4) Which of these reactions(s) will produce Saytzeff product?