Question

Consider the following processes : $\Delta H(kJ/mol)$
½ A → B + 150
3B → 2C + D -125
E + A → 2D +350
For B + D → E + 2C, ΔH will be-

• A. 325 kJ/mol
• B. 525 kJ/mol
• C. -175 kJ.mol
• D. -325 kJ/mol

Answer 1

Answer: (C)

$2(i)-(iii)+(ii)$
$\Delta H=2(150)-350-125$
$=-175kJ/mol$