1. Tardigrade
  2. Question
  3. Chemistry
  4. Consider the following processes: Δ H (kJ / mol) ½ A → B + 150 3B → 2C + D -125 E + A → 2D +350 For B + D → E + 2C, ΔH will be-

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Q. Consider the following processes : $\Delta H (kJ / mol)$
½ A → B + 150
3B → 2C + D -125
E + A → 2D +350
For B + D → E + 2C, ΔH will be-

AIPMTAIPMT 2011Thermodynamics

Solution:

$2(i) - (iii) + (ii)$
$\Delta H = 2(150) - 350 - 125$
$ = - 175 \, kJ / mol $