Consider the following complexes - (i) K2PtCl6 (i i) PtCl4.2NH3 (i i i) PtCl4.3NH3 (i v) PtCl4.5NH3 Their electrical conductances in aq. solutions are -

Question

Consider the following complexes - (i) K2PtCl6 (i i) PtCl4.2NH3 (i i i) PtCl4.3NH3 (i v) PtCl4.5NH3 Their electrical conductances in aq. solutions are - (A) 256,0,97,404 (B) 404,0,97,256 (C) 256,97,0,404 (D) 404,97,256,0

Tardigrade Admin · Accepted Answer

Coordination number of Pt is 6 hence I. K2[P t C l6] - Three ions II. [P t (N H3)2 C l4] - Zero ions III. [P t (N H3)3 C l3]Cl - Two ions IV. [P t (N H3)5 C l]Cl3 - Four ions Conductivity propto no. of ions

Q. Consider the following complexes -
$(i)$ $K_{2} PtC l_{6}$
$(ii)$ $PtC l_{4} .2 N H_{3}$
$(iii)$ $PtC l_{4} .3 N H_{3}$
$(i v)$ $PtC l_{4} .5 N H_{3}$
Their electrical conductances in aq. solutions are -

$256, 0, 97, 404$

$404, 0, 97, 256$

$256, 97, 0, 404$

$404, 97, 256, 0$

Coordination number of $Pt$ is $6$ hence
$I .$ $K_{2} [PtC l_{6}]$ - Three ions
$II .$ $[Pt (N H_{3})_{2} C l_{4}]$ - Zero ions
$III .$ $[Pt (N H_{3})_{3} C l_{3}] Cl$ - Two ions
$I V .$ $[Pt (N H_{3})_{5} Cl] C l_{3}$ - Four ions
Conductivity $\propto$ no. of ions

Q. Consider the following complexes - (i) K2​PtCl6​ (ii) PtCl4​.2NH3​ (iii) PtCl4​.3NH3​ (iv) PtCl4​.5NH3​ Their electrical conductances in aq. solutions are -

256,0,97,404

404,0,97,256

256,97,0,404

404,97,256,0