Question

Consider the following complexes -
$\left(i\right)$ $K_{2}PtCl_{6}$
$\left(i i\right)$ $PtCl_{4}.2NH_{3}$
$\left(i i i\right)$ $PtCl_{4}.3NH_{3}$
$\left(i v\right)$ $PtCl_{4}.5NH_{3}$
Their electrical conductances in aq. solutions are -

• A. $256,0,97,404$
• B. $404,0,97,256$
• C. $256,97,0,404$
• D. $404,97,256,0$

Answer 1

Answer: (A)

Coordination number of $Pt$ is $6$ hence
$I.$ $K_{2}\left[P t C l_{6}\right]$ - Three ions
$II.$ $\left[P t \left(N H_{3}\right)_{2} C l_{4}\right]$ - Zero ions
$III.$ $\left[P t \left(N H_{3}\right)_{3} C l_{3}\right]Cl$ - Two ions
$IV.$ $\left[P t \left(N H_{3}\right)_{5} C l\right]Cl_{3}$ - Four ions
Conductivity $ \propto $ no. of ions