Consider the following carbocations: I. Cl3 overset+C II. Cl2 overset+ CH III. Cl overset+ CH2 IV. overset+ CH3 The stability sequence follows the order

Question

Consider the following carbocations: I. Cl3 overset+C II. Cl2 overset+ CH III. Cl overset+ CH2 IV. overset+ CH3 The stability sequence follows the order (A) IV < I < III < II (B) I < II < III < IV (C) II < III < IV < I (D) III < I < II < IV

Tardigrade Admin · Accepted Answer

Electron withdrawing groups like —NO2, — X etc., decrease the stability of carbonium ion. So, the stability order is Cl3C+ < Cl2 overset+CH < Cl overset+CH2 < overset+CH3

Q. Consider the following carbocations :
I. $C l_{3} C +$
II. $C l_{2} C + H$
III. $Cl C + H_{2}$
IV. $C + H_{3}$
The stability sequence follows the order

IV < I < III < II

I < II < III < IV

II < III < IV < I

III < I < II < IV

Electron withdrawing groups like $— N O_{2}$ , $— X$ etc., decrease the stability of carbonium ion. So, the stability order is
$C l_{3} C^{+} < C l_{2}$ $C + H < Cl C + H_{2} < C + H_{3}$

Q. Consider the following carbocations : I. Cl3​C+ II. Cl2​C+H III. ClC+H2​ IV. C+H3​ The stability sequence follows the order