Consider an electron in a hydrogen atom, revolving in its second excited state (having radius 4.65 mathringA). The de-Broglie wavelength of this electron is :

Question

Consider an electron in a hydrogen atom, revolving in its second excited state (having radius 4.65 mathringA). The de-Broglie wavelength of this electron is : (A) 12.9 mathringA (B) 3.5 mathringA (C) 9.7 mathringA (D) 6.6 mathringA

Tardigrade Admin · Accepted Answer

2π rn = n λn λ3 = (2 π (4.65 × 10-10)/3) λ3 = 9.7 mathringA

Q. Consider an electron in a hydrogen atom, revolving in its second excited state (having radius $4.65 \overset{˚}{A}$ ). The de-Broglie wavelength of this electron is :

$12.9 \overset{˚}{A}$

$3.5 \overset{˚}{A}$

$9.7 \overset{˚}{A}$

$6.6 \overset{˚}{A}$

$2 π r_{n} = n λ_{n}$
$λ_{3} = \frac{2 π ( 4.65 \times 1 0 ^{- 10} )}{3}$
$λ_{3} = 9.7 \overset{˚}{A}$

Q. Consider an electron in a hydrogen atom, revolving in its second excited state (having radius 4.65A˚). The de-Broglie wavelength of this electron is :

12.9A˚

3.5A˚

9.7A˚

6.6A˚