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  4. Consider an electron in a hydrogen atom, revolving in its second excited state (having radius 4.65 mathringA). The de-Broglie wavelength of this electron is :

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Q. Consider an electron in a hydrogen atom, revolving in its second excited state (having radius $4.65\,\mathring{A}$). The de-Broglie wavelength of this electron is :

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Solution:

$2\pi r_n \, = \, n \lambda_n$
$\lambda_3 \, = \, \frac{2 \pi (4.65 \times 10^{-10})}{3}$
$\lambda_3 = 9.7\, \mathring{A}$