Consider a sample of oxygen behaving like an ideal gas. At 300 K, the ratio of root mean square (rms) velocity to the average velocity of gas molecule would be: (Molecular weight of oxygen is 32 g / mol; .R =8.3 J K -1 mol -1)

Question

Consider a sample of oxygen behaving like an ideal gas. At 300 K, the ratio of root mean square (rms) velocity to the average velocity of gas molecule would be: (Molecular weight of oxygen is 32 g / mol; .R =8.3 J K -1 mol -1) (A) √(3/3) (B) √(8/3) (C) √(3 π/8) (D) √(8 π/3)

Tardigrade Admin · Accepted Answer

V rms =√(3 RT / M ) V avg =√(8 RT /π) ( RT / M ) ( V rm s / V avg )=√(3 π/8)

Q. Consider a sample of oxygen behaving like an ideal gas. At $300 K$ , the ratio of root mean square (rms) velocity to the average velocity of gas molecule would be :
(Molecular weight of oxygen is $32 g / m o l$ ; $R = 8.3 J K^{- 1} m o l^{- 1})$

$\frac{3}{3}$

$\frac{8}{3}$

$\frac{3 π}{8}$

$\frac{8 π}{3}$

$V_{r m s} = \frac{3 RT}{M}$
$V_{a vg} = \frac{8 RT}{π} \frac{RT}{M}$
$\frac{V _{r m s}}{V _{a vg}} = \frac{3 π}{8}$

Q. Consider a sample of oxygen behaving like an ideal gas. At 300K, the ratio of root mean square (rms) velocity to the average velocity of gas molecule would be : (Molecular weight of oxygen is 32g/mol; R=8.3JK−1mol−1)

33​​

38​​

83π​​

38π​​