1. Tardigrade
  2. Question
  3. Physics
  4. Consider a sample of oxygen behaving like an ideal gas. At 300 K, the ratio of root mean square (rms) velocity to the average velocity of gas molecule would be: (Molecular weight of oxygen is 32 g / mol; .R =8.3 J K -1 mol -1)

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. Consider a sample of oxygen behaving like an ideal gas. At $300\,K$, the ratio of root mean square (rms) velocity to the average velocity of gas molecule would be :
(Molecular weight of oxygen is $32\,g / mol$; $\left.R =8.3 J K ^{-1} mol ^{-1}\right)$

JEE MainJEE Main 2021Kinetic Theory

Solution:

$V _{ rms }=\sqrt{\frac{3 RT }{ M }}$
$V _{ avg }=\sqrt{\frac{8 RT }{\pi} \frac{ RT }{ M }}$
$\frac{ V _{ rm s }}{ V _{ avg }}=\sqrt{\frac{3 \pi}{8}}$