Consider a cube of body-centered cubic unit cell of edge length a. Now atom at the body centre can be viewed to be lying on the corner of another cube 2 . Find the volume common to cube 1 and cube 2 .

Question

Consider a cube of body-centered cubic unit cell of edge length a. Now atom at the body centre can be viewed to be lying on the corner of another cube 2 . Find the volume common to cube 1 and cube 2 . (A) (a3/27) (B) (a3/64) (C) (a3/2 √2) (D) (a3/8)

Tardigrade Admin · Accepted Answer

Volume of cube =a3 , body centred atom can share to 8 such cubes. Hence volume common to cube 1 and 2 is one-eighth of its volume.

Q. Consider a cube of body-centered cubic unit cell of edge length a. Now atom at the body centre can be viewed to be lying on the corner of another cube $2$ . Find the volume common to cube $1$ and cube $2$ .

$\frac{a ^{3}}{27}$

$\frac{a ^{3}}{64}$

$\frac{a ^{3}}{2 2}$

$\frac{a ^{3}}{8}$

Volume of cube $= a^{3}$ , body centred atom can share to $8$ such cubes. Hence volume common to cube 1 and 2 is one-eighth of its volume.

Q. Consider a cube of body-centered cubic unit cell of edge length a. Now atom at the body centre can be viewed to be lying on the corner of another cube 2 . Find the volume common to cube 1 and cube 2 .

27a3​

64a3​

22​a3​

8a3​