Compound (X) on reduction with LiAlH4 gives a hydride (Y) containing 21.72% hydrogen along with other products. The compound (Y) reacts with air explosively resulting in boron trioxide. Compounds x and Y are respectively

Question

Compound (X) on reduction with LiAlH4 gives a hydride (Y) containing 21.72% hydrogen along with other products. The compound (Y) reacts with air explosively resulting in boron trioxide. Compounds x and Y are respectively (A) BCl3,B2H6 (B) B2H6,BCl3 (C) BF3,Al2O6 (D) B2H6,BF3

Tardigrade Admin · Accepted Answer

underset(X)4 B C l3+3LiAlH4 arrow underset(Y)2 B2 H6+3AlCl3+3LiCl Percentage of hydrogen in B2H6=(6/27.62)× 100=21.72 B2H6+3O2 overset E x p l o s i o n arrow B2O3+3H2O

Q. Compound (X) on reduction with $L i A l H_{4}$ gives a hydride (Y) containing 21.72% hydrogen along with other products. The compound (Y) reacts with air explosively resulting in boron trioxide. Compounds x and Y are respectively

$BC l_{3}, B_{2} H_{6}$

$B_{2} H_{6}, BC l_{3}$

$B F_{3}, A l_{2} O_{6}$

$B_{2} H_{6}, B F_{3}$

$(X) 4 BC l_{3} + 3 L i A l H_{4} \to (Y) 2 B_{2} H_{6} + 3 A lC l_{3} + 3 L i Cl$

Percentage of hydrogen in $B_{2} H_{6} = \frac{6}{27.62} \times 100 = 21.72$

$B_{2} H_{6} + 3 O_{2} \to E x pl os i o n B_{2} O_{3} + 3 H_{2} O$

Q. Compound (X) on reduction with LiAlH4​ gives a hydride (Y) containing 21.72% hydrogen along with other products. The compound (Y) reacts with air explosively resulting in boron trioxide. Compounds x and Y are respectively

BCl3​,B2​H6​

B2​H6​,BCl3​

BF3​,Al2​O6​

B2​H6​,BF3​