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Q. Compound (X) on reduction with $LiAlH_{4}$ gives a hydride (Y) containing 21.72% hydrogen along with other products. The compound (Y) reacts with air explosively resulting in boron trioxide. Compounds x and Y are respectively

NTA AbhyasNTA Abhyas 2020The p-Block Elements - Part2

Solution:

$\underset{\left(X\right)}{4 B C l_{3}}+3LiAlH_{4} \rightarrow \underset{\left(Y\right)}{2 B_{2} H_{6}}+3AlCl_{3}+3LiCl$

Percentage of hydrogen in $B_{2}H_{6}=\frac{6}{27.62}\times 100=21.72$

$B_{2}H_{6}+3O_{2}\overset{ E x p l o s i o n }{ \rightarrow }B_{2}O_{3}+3H_{2}O$