Question

Compound with the geometry square pyramidal and $s{p}^3{d}^2$ hybridisation is

• A. $XeO{F}_2$
• B. $XeO{F}_4$
• C. $Xe{O}_4$
• D. $Xe{O}_2{F}_2$

Answer 1

Answer: (B)

Hybridization of an atom is identified by calculating the sum of sigma bonds and lone pairs.
If a sum of sigma bonds and lone pairs is $2sp$ hybridization
If a sum of sigma bonds and lone pairs is $3s{p}^2$ hybridization
If a sum of sigma bonds and lone pairs is $4s{p}^3$ hybridization
If a sum of sigma bonds and lone pairs is $2s{p}^{3}d$ hybridization
If a sum of sigma bonds and lone pairs is $2s{p}^3{d}^2$ hybridization.
So the given molecule has $5$ sigma bonds $1$ lone pair so the sum is $6.$
So its hybridization is sp ${}^3{d}^2$ and the shape is square pyramidal.