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Q.
Compound with the geometry square pyramidal and $s p^{3} d^{2}$ hybridisation is
The p-Block Elements - Part2
Solution:
Hybridization of an atom is identified by calculating the sum of sigma bonds and lone pairs.
If a sum of sigma bonds and lone pairs is $2 \,sp$ hybridization
If a sum of sigma bonds and lone pairs is $3\, sp ^{2}$ hybridization
If a sum of sigma bonds and lone pairs is $4 \,sp ^{3}$ hybridization
If a sum of sigma bonds and lone pairs is $2 \,sp ^{3} \,d$ hybridization
If a sum of sigma bonds and lone pairs is $2 \,sp ^{3}\, d ^{2}$ hybridization.
So the given molecule has $5$ sigma bonds $1$ lone pair so the sum is $6 .$
So its hybridization is sp $^{3}\, d ^{2}$ and the shape is square pyramidal.