Compound (A) xrightarrow[HlO4]2 textmol of 2 mol of glyoxalic acid.The compound (A) is:

Question

Compound (A) xrightarrow[HlO4]2 textmol of 2 mol of glyoxalic acid.The compound (A) is: (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Glyoxalic acid is (OHC-COOH). Proceed reverse: <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/08d86918e8fd912c14c8bc13e88cc7ec-.png" /> The two (OH) groups must be syn (cis) position for periodic oxidation. So the answer is (d)

Q. Compound (A) $2 mol of H l O_{4}$ 2 mol of glyoxalic acid.The compound (A) is:

Glyoxalic acid is $(O H C - COO H)$ . Proceed reverse:

The two $(O H)$ groups must be syn (cis) position for periodic oxidation. So the answer is (d)

Q. Compound (A) 2mol ofHlO4​​ 2 mol of glyoxalic acid.The compound (A) is:

Glyoxalic acid is (OHC−COOH). Proceed reverse: The two (OH) groups must be syn (cis) position for periodic oxidation. So the answer is (d)

Q. Compound (A) $2 mol of H l O_{4}$ 2 mol of glyoxalic acid.The compound (A) is:

Glyoxalic acid is $(O H C - COO H)$ . Proceed reverse:

The two $(O H)$ groups must be syn (cis) position for periodic oxidation. So the answer is (d)