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  4. Compound (A) xrightarrow[HlO4]2 textmol of 2 mol of glyoxalic acid.The compound (A) is:

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Q. Compound (A) $\xrightarrow[HlO_4]{2 \text{mol of}}$ 2 mol of glyoxalic acid.The compound (A) is:

Redox Reactions

Solution:

Glyoxalic acid is $(OHC-COOH)$. Proceed reverse:
image
The two $(OH)$ groups must be syn (cis) position for periodic oxidation. So the answer is (d)