Compound A reacts with NH 4 Cl and forms a compound B. Compound B reacts with H 2 O and excess of CO 2 to form compound C which on passing through or reaction with saturated NaCl solution forms sodium hydrogen carbonate. Compound A , B and C, are respectively.

Question

Compound A reacts with NH 4 Cl and forms a compound B. Compound B reacts with H 2 O and excess of CO 2 to form compound C which on passing through or reaction with saturated NaCl solution forms sodium hydrogen carbonate. Compound A , B and C, are respectively. (A) CaCl 2, NH 4+,( NH 4)2 CO 3 (B) CaCl 2, NH 3, NH 4 HCO 3 (C) Ca ( OH )2, NH 3, NH 4 HCO 3 (D) Ca ( OH )2, NH 4+,( NH 4)2 CO 3

Tardigrade Admin · Accepted Answer

underset text (A) Ca ( OH )2+2 NH 4 Cl xrightarrow Δ underset text (B) 2NH3 + CaCl 2+2 H 2 O underset text (B) NH 3+ H 2 O + underset text (exc) CO 2 longrightarrow underset text (C) NH 4 HCO 3 underset(c)NH 4 HCO 3+ NaCl longrightarrow NaHCO 3 downarrow+ NH 4 Cl

Q. Compound A reacts with $N H_{4} Cl$ and forms a compound B. Compound B reacts with $H_{2} O$ and excess of $C O_{2}$ to form compound $C$ which on passing through or reaction with saturated $N a Cl$ solution forms sodium hydrogen carbonate. Compound $A, B$ and $C$ , are respectively.

$C a C l_{2}, N H_{4}^{+}, (N H_{4})_{2} C O_{3}$

$C a C l_{2}, N H_{3}, N H_{4} H C O_{3}$

$C a (O H)_{2}, N H_{3}, N H_{4} H C O_{3}$

$C a (O H)_{2}, N H_{4}^{+}, (N H_{4})_{2} C O_{3}$

$(A) C a (O H)_{2} + 2 N H_{4} Cl Δ (B) 2 N H_{3} + C a C l_{2} + 2 H_{2} O$
$(B) N H_{3} + H_{2} O + (exc) C O_{2} ⟶ (C) N H_{4} H C O_{3}$
$(c) N H_{4} H C O_{3} + N a Cl ⟶ N a H C O_{3} ↓ + N H_{4} Cl$

Q. Compound A reacts with NH4​Cl and forms a compound B. Compound B reacts with H2​O and excess of CO2​ to form compound C which on passing through or reaction with saturated NaCl solution forms sodium hydrogen carbonate. Compound A,B and C, are respectively.

CaCl2​,NH4+​,(NH4​)2​CO3​

CaCl2​,NH3​,NH4​HCO3​

Ca(OH)2​,NH3​,NH4​HCO3​

Ca(OH)2​,NH4+​,(NH4​)2​CO3​