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  4. Compound A reacts with NH 4 Cl and forms a compound B. Compound B reacts with H 2 O and excess of CO 2 to form compound C which on passing through or reaction with saturated NaCl solution forms sodium hydrogen carbonate. Compound A , B and C, are respectively.

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Q. Compound A reacts with $NH _4 Cl$ and forms a compound B. Compound B reacts with $H _2 O$ and excess of $CO _2$ to form compound $C$ which on passing through or reaction with saturated $NaCl$ solution forms sodium hydrogen carbonate. Compound $A , B$ and $C$, are respectively.

JEE MainJEE Main 2023The p-Block Elements

Solution:

$\underset{\text { (A) }}{ Ca ( OH )_2}+2 NH _4 Cl \xrightarrow {\Delta} \underset{\text { (B) }}{2NH_3} + CaCl _2+2 H _2 O$
$\underset{\text { (B) }}{ NH _3}+ H _2 O +\underset{\text { (exc) }}{ CO _2} \longrightarrow \underset{\text { (C) }}{ NH _4 HCO _3}$
$\underset{(c)}{NH _4 HCO _3}+ NaCl \longrightarrow NaHCO _3 \downarrow+ NH _4 Cl$