Compared to the mass of lightest nucleus mass an electron is only:

Question

Compared to the mass of lightest nucleus mass an electron is only: (A) 1/80 (B) 1/1800 (C) 1/800 (D) 1/1000

Tardigrade Admin · Accepted Answer

Mass of electron (me)=9.1 × 10-31 kg. Highest nucleus is of hydrogen. Mass of H-nucleus mH=1.67 × 10-27 kg (me/mH)=(9.1 × 10-31/1.67 × 10-27) =(1/1800) (approx)

Q. Compared to the mass of lightest nucleus mass an electron is only:

1/80

1/1800

1/800

1/1000

Mass of electron $(m_{e}) = 9.1 \times 1 0^{- 31} k g$ .
Highest nucleus is of hydrogen.
Mass of H-nucleus $m_{H} = 1.67 \times 1 0^{- 27} k g$
$\frac{m _{e}}{m _{H}} = \frac{9.1 \times 1 0 ^{- 31}}{1.67 \times 1 0 ^{- 27}}$
$= \frac{1}{1800}$ (approx)

Q. Compared to the mass of lightest nucleus mass an electron is only:

1/80

1/1800

1/800

1/1000

Mass of electron (me​)=9.1×10−31kg. Highest nucleus is of hydrogen. Mass of H-nucleus mH​=1.67×10−27kg mH​me​​=1.67×10−279.1×10−31​ =18001​ (approx)

Mass of electron $(m_{e}) = 9.1 \times 1 0^{- 31} k g$ .
Highest nucleus is of hydrogen.
Mass of H-nucleus $m_{H} = 1.67 \times 1 0^{- 27} k g$
$\frac{m _{e}}{m _{H}} = \frac{9.1 \times 1 0 ^{- 31}}{1.67 \times 1 0 ^{- 27}}$
$= \frac{1}{1800}$ (approx)