Common salt obtained from sea - water contains 96 % NaCl by mass. The approximate number of molecules of NaCl present in 10.0 g of the common salt is: (At. wt. Na =23 )

Question

Common salt obtained from sea - water contains 96 % NaCl by mass. The approximate number of molecules of NaCl present in 10.0 g of the common salt is: (At. wt. Na =23 ) (A) 1021 (B) 1022 (C) 1023 (D) 1024

Tardigrade Admin · Accepted Answer

Mass of NaCl =10 × 0.96=9.6 gm moles of NaCl =(9.6/58.5) no. of molecules =(9.6/58.5) × 6.023 × 1023 ≃ 1023

Q. Common salt obtained from sea - water contains $96% N a Cl$ by mass. The approximate number of molecules of $N a Cl$ present in $10.0 g$ of the common salt is : (At. wt. $N a = 23$ )

$1 0^{21}$

$1 0^{22}$

$1 0^{23}$

$1 0^{24}$

Mass of $N a Cl = 10 \times 0.96 = 9.6 g m$
moles of $N a Cl = \frac{9.6}{58.5}$
no. of molecules $= \frac{9.6}{58.5} \times 6.023 \times 1 0^{23}$
$≃ 1 0^{23}$

Q. Common salt obtained from sea - water contains 96%NaCl by mass. The approximate number of molecules of NaCl present in 10.0g of the common salt is : (At. wt. Na=23 )

1021

1022

1023

1024