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  3. Chemistry
  4. Common salt obtained from sea - water contains 96 % NaCl by mass. The approximate number of molecules of NaCl present in 10.0 g of the common salt is: (At. wt. Na =23 )

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Q. Common salt obtained from sea - water contains $96 \% NaCl$ by mass. The approximate number of molecules of $NaCl$ present in $10.0\, g$ of the common salt is : (At. wt. $Na =23$ )

Solution:

Mass of $NaCl =10 \times 0.96=9.6\, gm$
moles of $NaCl =\frac{9.6}{58.5}$
no. of molecules $=\frac{9.6}{58.5} \times 6.023 \times 10^{23}$
$\simeq 10^{23}$