Common salt obtained from sea water contains 95 % NaCl by mass. The approximate number of molecules present in 10.0 g of the salt is

Question

Common salt obtained from sea water contains 95 % NaCl by mass. The approximate number of molecules present in 10.0 g of the salt is (A) 1021 (B) 1022 (C) 1023 (D) 1024

Tardigrade Admin · Accepted Answer

58.5 g of NaCl contains 6.023 × 1023 molecules 10 g will contain 1.03 × 1023 molecules of NaCl Since, it contain 95 % NaCl , so, total number of molecules =(95/100) × 1.03 × 1023 =0.98 × 1023 ≃ 1023

Q. Common salt obtained from sea water contains $95% N a Cl$ by mass. The approximate number of molecules present in $10.0 g$ of the salt is

$1 0^{21}$

$1 0^{22}$

$1 0^{23}$

$1 0^{24}$

$58.5 g$ of $N a Cl$ contains $6.023 \times 1 0^{23}$ molecules

$10 g$ will contain $1.03 \times 1 0^{23}$ molecules of $N a Cl$

Since, it contain $95% N a Cl$ , so, total number of molecules

$= \frac{95}{100} \times 1.03 \times 1 0^{23}$

$= 0.98 \times 1 0^{23} ≃ 1 0^{23}$

Q. Common salt obtained from sea water contains 95%NaCl by mass. The approximate number of molecules present in 10.0g of the salt is

1021

1022

1023

1024