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  4. Common salt obtained from sea water contains 95 % NaCl by mass. The approximate number of molecules present in 10.0 g of the salt is

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Q. Common salt obtained from sea water contains $95 \%\, NaCl$ by mass. The approximate number of molecules present in $10.0 \,g$ of the salt is

Some Basic Concepts of Chemistry

Solution:

$58.5\, g$ of $NaCl$ contains $6.023 \times 10^{23}$ molecules

$10 \,g$ will contain $1.03 \times 10^{23}$ molecules of $NaCl$

Since, it contain $95 \% \,NaCl $, so, total number of molecules

$=\frac{95}{100} \times 1.03 \times 10^{23}$

$=0.98 \times 10^{23} \simeq 10^{23}$