Coefficient of linear expansion of material of resistor is α. Its temperature coefficient of resistivity and resistance are αρ and αR respectively, then correct relation is

Question

Coefficient of linear expansion of material of resistor is α. Its temperature coefficient of resistivity and resistance are αρ and αR respectively, then correct relation is (A) αR=αρ-α (B) αR=αp+α (C) αR=αρ+3 α (D) αR=αρ-3 α

Tardigrade Admin · Accepted Answer

R=(ρ l/A) (Δ R/R)=(Δ P/P)+(Δ l/l)-(D A/A) αR=αP+αR-2 α αR=αp-α

Q. Coefficient of linear expansion of material of resistor is $α$ . Its temperature coefficient of resistivity and resistance are $α_{ρ}$ and $α_{R}$ respectively, then correct relation is

$α_{R} = α_{ρ} - α$

$α_{R} = α_{p} + α$

$α_{R} = α_{ρ} + 3 α$

$α_{R} = α_{ρ} - 3 α$

$R = \frac{ρl}{A}$
$\frac{Δ R}{R} = \frac{Δ P}{P} + \frac{Δ l}{l} - \frac{D A}{A}$
$α_{R} = α_{P} + α_{R} - 2 α$
$α_{R} = α_{p} - α$

Q. Coefficient of linear expansion of material of resistor is α. Its temperature coefficient of resistivity and resistance are αρ​ and αR​ respectively, then correct relation is

αR​=αρ​−α

αR​=αp​+α

αR​=αρ​+3α

αR​=αρ​−3α