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Q. Coefficient of linear expansion of material of resistor is $\alpha$. Its temperature coefficient of resistivity and resistance are $\alpha_{\rho}$ and $\alpha_{R}$ respectively, then correct relation is

Current Electricity

Solution:

$R=\frac{\rho l}{A}$
$\frac{\Delta R}{R}=\frac{\Delta P}{P}+\frac{\Delta l}{l}-\frac{D A}{A}$
$\alpha_{R}=\alpha_{P}+\alpha_{R}-2 \alpha$
$\alpha_{R}=\alpha_{p}-\alpha$