Cobalt chloride when dissolved in water forms pink colored complex X which has octahedral geometry. This solution on treating with cone HCl forms deep blue complex, underlineY which has a underlineZ geometry. X, Y and Z, respectively, are

Question

Cobalt chloride when dissolved in water forms pink colored complex X which has octahedral geometry. This solution on treating with cone HCl forms deep blue complex, underlineY which has a underlineZ geometry. X, Y and Z, respectively, are (A) X =[ Co ( H 2 O )4 Cl 2]+, Y =[ CoCl 4]2-, Z = Tetrahedral (B) X =[ Co ( H 2 O )6]2+, Y =[ CoCl 6]3-, Z = Octahedral (C) X =[ Co ( H 2 O )6]2+, Y =[ CoCl 4]2-, Z = Tetrahedral (D) X =[ Co ( H 2 O )6]3+, Y =[ CoCl 6]3-, Z = Octahedral

Tardigrade Admin · Accepted Answer

Correct answer is (c) X =[ Co ( H 2 O )6]2+, Y =[ CoCl 4]2-, Z = Tetrahedral

Q. Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $H Cl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry. $X, Y$ and $Z$ , respectively, are

$X = [C o (H_{2} O)_{4} C l_{2}]^{+}, Y = [C o C l_{4}]^{2 -}, Z =$ Tetrahedral

$X = [C o (H_{2} O)_{6}]^{2 +}, Y = [C o C l_{6}]^{3 -}, Z =$ Octahedral

$X = [C o (H_{2} O)_{6}]^{2 +}, Y = [C o C l_{4}]^{2 -}, Z =$ Tetrahedral

$X = [C o (H_{2} O)_{6}]^{3 +}, Y = [C o C l_{6}]^{3 -}, Z =$ Octahedral

Correct answer is (c) $X = [C o (H_{2} O)_{6}]^{2 +}, Y = [C o C l_{4}]^{2 -}, Z =$ Tetrahedral

Q. Cobalt chloride when dissolved in water forms pink colored complex X which has octahedral geometry. This solution on treating with cone HCl forms deep blue complex, Y​ which has a Z​ geometry. X,Y and Z, respectively, are

X=[Co(H2​O)4​Cl2​]+,Y=[CoCl4​]2−,Z= Tetrahedral

X=[Co(H2​O)6​]2+,Y=[CoCl6​]3−,Z= Octahedral

X=[Co(H2​O)6​]2+,Y=[CoCl4​]2−,Z= Tetrahedral

X=[Co(H2​O)6​]3+,Y=[CoCl6​]3−,Z= Octahedral