[Co(C2O4)3]3- is a diamagnetic complex because

Question

[Co(C2O4)3]3- is a diamagnetic complex because (A) C2O2-4 is strong field ligand hence causes pairing of electrons (B) C2O2-4 is a bidentate ligand hence causes pairing of electrons (C) Co3+ is a strong central atom hence in all complexes of Co3+ electrons are paired (D) C2O2-4 is a strong field ligand hence causes splitting of d-orbitals

Tardigrade Admin · Accepted Answer

[Co(C2O4)3]3-: <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/06f982e3494cb2183097cb72a5853cc9-.png" />

Q. $[C o (C_{2} O_{4})_{3}]^{3 -}$ is a diamagnetic complex because

$C_{2} O_{4}^{2 -}$ is strong field ligand hence causes pairing of electrons

$C_{2} O_{4}^{2 -}$ is a bidentate ligand hence causes pairing of electrons

$C o^{3 +}$ is a strong central atom hence in all complexes of $C o^{3 +}$ electrons are paired

$C_{2} O_{4}^{2 -}$ is a strong field ligand hence causes splitting of $d$ -orbitals

$[C o (C_{2} O_{4})_{3}]^{3 -}$ :

Q. [Co(C2​O4​)3​]3− is a diamagnetic complex because

C2​O42−​ is strong field ligand hence causes pairing of electrons

C2​O42−​ is a bidentate ligand hence causes pairing of electrons

Co3+ is a strong central atom hence in all complexes of Co3+ electrons are paired

C2​O42−​ is a strong field ligand hence causes splitting of d-orbitals