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Chemistry
[Co(C2O4)3]3- is a diamagnetic complex because
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Q. $[Co(C_{2}O_{4})_{3}]^{3-}$ is a diamagnetic complex because
Coordination Compounds
A
$C_{2}O^{2-}_{4}$ is strong field ligand hence causes pairing of electrons
75%
B
$C_{2}O^{2-}_{4}$ is a bidentate ligand hence causes pairing of electrons
12%
C
$Co^{3+}$ is a strong central atom hence in all complexes of $Co^{3+ }$ electrons are paired
0%
D
$C_{2}O^{2-}_{4}$ is a strong field ligand hence causes splitting of $d$-orbitals
12%
Solution:
$[Co(C_{2}O_{4})_{3}]^{3-}$ :
