Question

Choose the correct options using the $V-T$ diagram

• A. $P_1=P_2$
• B. $P_1>P_2$
• C. $P_1<P_2$
• D. Cannot say anything

Answer 1

Answer: (C)

Comparing the curve with equation of straight line
$y=mx+c$
we get
$V=aT+b$
where $a=$ slope,
$b=$ constant

we know that ideal gas equation of a gas is
$PV=nRT$
Putting the value of volume as the above equation
$P=\frac{nRT}{aT+b}=\frac{nR}{a+\frac{b}{T}}$

we know that $T_2>T_1$ (from the graph)
so $\frac{b}{T_2}<\frac{b}{T_1}$
we can conclude
$\therefore P_2>P_1$