Choose the correct length ( L ) versus square of time period ( T 2. ) graph for a simple pendulum executing simple harmonic motion.

Question

Choose the correct length ( L ) versus square of time period ( T 2. ) graph for a simple pendulum executing simple harmonic motion. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

T =2 π √(ℓ/ g ) T 2 =(4 π2/ g ) × ℓ T 2 α ℓ

Q. Choose the correct length $(L)$ versus square of time period $(T^{2}$ ) graph for a simple pendulum executing simple harmonic motion.

$T = 2 π \frac{ℓ}{g}$
$T^{2} = \frac{4 π ^{2}}{g} \times ℓ$
$T^{2} α ℓ$

Q. Choose the correct length (L) versus square of time period (T2 ) graph for a simple pendulum executing simple harmonic motion.

T=2πgℓ​​ T2=g4π2​×ℓ T2αℓ

Q. Choose the correct length $(L)$ versus square of time period $(T^{2}$ ) graph for a simple pendulum executing simple harmonic motion.

$T = 2 π \frac{ℓ}{g}$
$T^{2} = \frac{4 π ^{2}}{g} \times ℓ$
$T^{2} α ℓ$