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Q. Choose the correct length $( L )$ versus square of time period $\left( T ^2\right.$ ) graph for a simple pendulum executing simple harmonic motion.

JEE MainJEE Main 2023Oscillations

Solution:

$T =2 \pi \sqrt{\frac{\ell}{ g }} $
$ T ^2 =\frac{4 \pi^2}{ g } \times \ell $
$ T ^2 \alpha \ell$