Chlorine is prepared in the laboratory by treating manganese dioxide ( MnO 2) with aqueous hydrochloric acid according to the reaction 4 HCl (a q)+ MnO 2(s) arrow 2 H 2 O (l)+ MnCl 2(a q)+ Cl 2(g) How many grams of HCl will react with 5.0 g of manganese dioxide?

Question

Chlorine is prepared in the laboratory by treating manganese dioxide ( MnO 2) with aqueous hydrochloric acid according to the reaction 4 HCl (a q)+ MnO 2(s) arrow 2 H 2 O (l)+ MnCl 2(a q)+ Cl 2(g) How many grams of HCl will react with 5.0 g of manganese dioxide? (A) 6.4 g HCl (B) 4.8 g HCl (C) 8.4 g HCl (D) 7.2 g HCl

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/6b6c9fcba23a395fa1e26d46781c456b-.png" /> 86.9 g of MnO 2 reacts with HCl =146 g Then 5.0 g will react with (146/86.9) × 5.0=8.4 g

$6.4 g H Cl$

$4.8 g H Cl$

$8.4 g H Cl$

$7.2 g H Cl$

$86.9 g$ of $M n O_{2}$ reacts with $H Cl = 146 g$

Then $5.0 g$ will react with $\frac{146}{86.9} \times 5.0 = 8.4 g$

Q. Chlorine is prepared in the laboratory by treating manganese dioxide (MnO2​) with aqueous hydrochloric acid according to the reaction 4HCl(aq)​+MnO2(s)​→2H2​O(l)​+MnCl2(aq)​+Cl2(g)​ How many grams of HCl will react with 5.0g of manganese dioxide?

6.4gHCl

4.8gHCl

8.4gHCl

7.2gHCl

86.9g of MnO2​ reacts with HCl=146g Then 5.0g will react with 86.9146​×5.0=8.4g

$6.4 g H Cl$

$4.8 g H Cl$

$8.4 g H Cl$

$7.2 g H Cl$

$86.9 g$ of $M n O_{2}$ reacts with $H Cl = 146 g$

Then $5.0 g$ will react with $\frac{146}{86.9} \times 5.0 = 8.4 g$