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Q. Chlorine is prepared in the laboratory by treating manganese dioxide $\left( MnO _{2}\right)$ with aqueous hydrochloric acid according to the reaction
$4 HCl _{(a q)}+ MnO _{2(s)} \rightarrow 2 H _{2} O _{(l)}+ MnCl _{2(a q)}+ Cl _{2(g)}$
How many grams of $HCl$ will react with $5.0 \,g$ of manganese dioxide?

Some Basic Concepts of Chemistry

Solution:

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$86.9 \,g$ of $MnO _{2}$ reacts with $HCl =146 \,g$

Then $5.0\, g$ will react with $\frac{146}{86.9} \times 5.0=8.4 \,g$