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Question
Chemistry
Chlorine gas is prepared by reaction of H2SO4 with MnO2 and NaCl. What volume of Cl2 will be produced at STP if 50 g of NaCl is taken in the reaction?
Q. Chlorine gas is prepared by reaction of
H
2
S
O
4
with
M
n
O
2
and NaCl. What volume of
C
l
2
will be produced at STP if 50 g of NaCl is taken in the reaction?
3090
175
NTA Abhyas
NTA Abhyas 2020
Some Basic Concepts of Chemistry
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A
19.14 L
14%
B
22.4 L
0%
C
11.2 L
29%
D
9.57 L
57%
Solution:
(
2
×
58.5
=
117
g
)
2
moles
2
N
a
Cl
+
M
n
O
2
+
3
H
2
S
O
4
→
2
N
a
H
S
O
4
+
M
n
S
O
4
+
22.4
L
(
STP
)
1
mole
C
l
2
+
2
H
2
O
117 g of NaCl
≡
22.4
L of
C
l
2
50 g of
N
a
Cl
≡
117
22.4
×
50
=
9.57
L of
C
l
2
at STP.